Acid-Base Equilibria
38) pH = 12.00 [Ca(OH)2] = ?
Ca(OH)2(s) Ca2+(aq) + 2OH–(aq)
[H+] = 10-pH = 10-12.00 = 1.0 x 10-12 M
Kw = [H+] x [OH–] = 1.00 x 10-14
[OH–] = 1.00 x 10-14/1.0 x 10-12 = 1.0 x 10-2 M
[Ca(OH)2] = 1.0 x 10-2 mol OH–/L x 1 mol Ca(OH)2/2 mol OH– = 5.0 x 10-3 M
Related
