pSol60

Properties of Solutions

60) m₁ = 5.00 g la      m₂ = 0.100 kg C₆H₆      T_f = 4.1°C      T_f^° = 5.5°C      K_f = 5.12°C/m

      ΔT_f = K_f x m x i

      ΔT_f = T_f^° – T_f = K_f x m x i

      5.5°C – 4.1°C = 5.12°C/m x m x i

      1.4°C = 5.12°C/m x m x 1

      m = 0.27  m

      m = n/kg

      n = m x kg = 0.27 m x 0.100 kg = 0.027 mol la

      MM = m/n = 5.00 g/0.027 mol = 180 g/mol