Equilibrium Calculations

Which of the adhering to is the appropriate ICE table for this stability?

( a)

	NH3	O2	N2O	H2O
[] i	0.8	0.8	0	0
[] c	-2 x	-2 x	+ x	+3 x
[] e	0.8 – 2x	0.8 – 2x	x	3x

( b)

	NH3	O2	N2O	H2O
[] i	0.2	0.2	0	0
[] c	-6 x	-6 x	+6 x	+6 x
[] e	0.2 – 6x	0.2 – 6x	4x	4x

( c)

	NH3	O2	N2O	H2O
[] i	0.8	0.8	0	0
[] c	– x	– x	+ x	+ x
[] e	0.8 – x	0.8 – x	x	x

( d)

	NH3	O2	N2O	H2O
[] i	0.2	0.2	0	0
[] c	-2 x	-2 x	+ x	+3 x
[] e	0.2 – 2x	0.2 – 2x	x	3x

5

) You have 0.80 moles NH₃ as well as 0.40 moles O₂ existing originally in a 4-L flask. You enable the response to run up until it gets to balance as revealed listed below.

4NH₃( g) + 5O₂( g) < img elevation=" 12" src=" https://mmsphyschem.com/wp-content/uploads/2021/02/eqarrow-5646762.gif "size= "39 "> 4NO( g) +6H 2 O (g) Which of the complying with

is

the

	right ICE table for this stability?( a) NH	3O	2N	2O
H 2 O [] i 0.80 0.40	0 0	[]	. c	– x
-x+ x+ x [] e 0.80- x 0.40	– x	x	x	( b
)NH 3 O 2 N 2 O H 2 O [.	] i 0.20 0.10	0 0 [	. ] c -4 x	-5 x

+4 x

	+6x	[]	.e0.20- 4x 0.10- 5x 4x	6x( c) NH3
O 2 N 2 O H 2 O [] i 0.80 0.40	0 0	[]	. c -4 x -5 x +4	x +6 x [] e 0.20- 4x	0.40- 5x 4x 6x (d) NH 3 O 2 N 2 O H	2 O []	. i 0.20 0.10	0 0 []	. c -30 x -30 x
+30 x +30 x [] e 0.20- 30x 0.10- 30x	30x 30x 6)	The complying with response has	an balance constant of 50	. at

a provided temperature level

	. I2	(g	)+H	2(
g)< img elevation =" 12" src=" https://mmsphyschem.com/wp-content/uploads/2021/02/eqarrow-5646762.gif" size=" 39	” >	2HI (	g )
If you have 0.59 moles of I 2( g	) and also 0.59 moles of H 2	( g)	in a	0.50-L container at first
, the number of moles of H 2 will be existing	when the system gets to stability?( a) 0.14 moles( b) 0.02 moles	( c)	0.13 moles( d) 0.070 moles( e) 0.26 moles.

7)

	You have 0.50 mol	each of H	2O	as well as Cl 2O
existing at first in a 1.0-L flask. The	system	is enabled to get to balance	at 25 C	as revealed
listed below. H 2 O( g)+ Cl 2 O (	g)< img elevation=" 12	” src	=” https://mmsphyschem.com/wp-content/uploads/2021/02/eqarrow-5646762.gif” size =” 39
“> 2HOCl( g) There is 0.13 mol HOCl existing at stability. What is K ?( a) 8.9 x	10 -2 (b)	6.8 x	10 -2(

c) 6.8 x 10

-1 ( d ) 1.2 x 10 -1( e) 1.0. 8 )The adhering to response has a stability continuous, K c, of 12 at 900 ° C. CARBON MONOXIDE

( g) + Cl 2( g) COCl 2( g) If you have 0.57 moles of Cl 2 (g) and also 0.57 moles of carbon monoxide (g) in a 1.0-L container at first,

the amount of moles

of carbon monoxide will exist when the

system gets to stability?

( a) 0.020 moles

( b) 0.18 moles

( c) 0.040 moles( d) 0.50 moles Residence Online Assignments

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