38) The reason for each of the choices below is the same. The more readily a substance is reduced (the more positive the E°red or the more negative the E°ox ) the stronger the oxidizing agent.
(a) Ce4+(aq) + e- Ce3+(aq) E°red = +1.61 V
Br2(l) + 2e- 2Br-(aq) E°red = +1.065 V
H2O2(aq) + 2H+(aq) + 2e- 2H2O(l) E°red = +1.776 V
Zn(s) + 2e- E°red = ??? (Zn is not very likely to be reduced.)
H2O2(aq) is the strongest oxidizing agent and Zn(s) is the weakest.
(b) F2(g) + 2e- 2F-(aq) E°red = +2.87 V
Zn2+(aq) + 2e- Zn(s) E°red = -0.763 V
N2(g) + 5H+(aq) + 4e- N2H5+(aq) E°red = -0.23 V
I2(s) + 2e- 2I-(aq) E°red = +0.536 V
NO3-(aq) + 4H+(aq) + 3e- NO(g) + 2H2O(l) E°red = +0.96 V
Zn(s) is the strongest reducing agent and F- is the weakest.