Properties of Solutions

 

40)  D = 1.42 g/mL

       [HNO3] = 16 M

      
       HNO3(aq)  H+(aq) + NO3-(aq)

       m% = msolute/msol'n x 100%

       Assume V = 1.00 L

       D = M/V

       M = D x V = 1.42 g/mL x 1.00 L x 103 mL/L = 1420 g sol'n

       [HNO3] = n/V

       n = [HNO3] x V = 16 mol HNO3/L x 1.00 L = 16 mol HNO3

       m = 16 mol HNO3 x 63.02 g HNO3/1 mol HNO3 = 1.0 x 103 g HNO3

       m% = 1.0 x 103 g HNO3/1420 g sol'n x 100% = 70.% HNO3