Chemical Kinetics

 

 42) (a) Ea = 160.0 kJ/mol          T = 500 K          R = 8.31 J/mol•K

 

             f = e-Ea/RT

             Ea/RT = 160.0 kJ/mol/(8.31 J/molK x 1 kJ/103 J x 500 K) = 38.5

             f = e-38.5 = 2 x 10-17

            

       (b) T = 510 K

 

             Ea/RT = 160.0 kJ/mol/(8.31 J/molK x 1 kJ/103 J x 510 K) = 37.8

             f = e-37.8 = 4 x 10-17

            

             f510/f500 = 4 x 10-17/2 x 10-17 = 2

 

             An increase in temperature of 10 K results in twice the number of molecules having this energy.