Acid-Base Equilibria

 

46) [ClCH2COOH] = 0.100 M          %ion = 11.0%             

      

            ClCH2COOH(aq) H+(aq) + ClCH2COO-(aq)

      [ ]i         0.100                            0                   0

      [ ]c          -0.011                       +0.011          +0.011

      [ ]e           0.100-0.011               0.011            0.011

 

      %ion = [H+]/[ClCH2COOH] x 100%

      [H+]/[ClCH2COOH] = 0.110

      [H+] = 0.110 x [ClCH2COOH] = 0.110 x 0.100 M = 0.011 M

 

      [H+] = [ClCH2COO-] = 0.011 M

      [ClCH2COOH]eq = 0.100 M - 0.011 M = 0.089 M

      Ka = [H+] x [ClCH2COO-]/[ClCH2COOH]

      Ka = 0.011 x 0.011/0.089 = 1.4 x 10-3